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2KHCo3 + 2NaOH → K2Co3 + Na2Co3 + 2H2O
Instructions
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
[external_link_head][external_link offset=1]- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- Ionic charges are not yet supported and will be ignored.
- Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
- Compound states [like (s) (aq) or (g)] are not required.
- You can use parenthesis () or brackets [].
How To Balance Equations
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Balance The Equation: KHCo3 + NaOH = K2Co3 + Na2Co3 + H2O 1. Label Each Compound With a Variable aKHCo3 + bNaOH = cK2Co3 + dNa2Co3 + fH2O 2. Create a System of Equations, One Per Element K: 1a + 0b = 2c + 0d + 0f H: 1a + 1b = 0c + 0d + 2f Co: 3a + 0b = 3c + 3d + 0f Na: 0a + 1b = 0c + 2d + 0f O: 0a + 1b = 0c + 0d + 1f 3. Solve For All Variables a = 2 b = 2 c = 1 d = 1 f = 2 4. Substitute and Verify Result 2KHCo3 + 2NaOH = K2Co3 + Na2Co3 + 2H2O L R K: 2 2 ✔️ H: 4 4 ✔️ Co: 6 6 ✔️ Na: 2 2 ✔️ O: 2 2 ✔️
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